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1) ABC is a triangle, right angled at A. The resultant of the forces acting along AB, AC with magnitudes 1/AB and 1/AC respectively is the force along AD , where D is the foot of the perpendicular from A onto BC. The magnitude of the resultant is
1 )  
AB2 + AC2
(AB)2(AC)2
2 )  
(AB)(AC)
AB + AC
3 )  
1  +  1
AB AC
4 )  
1
AD
see the answer    see the solution

ANSWERS

1) 4

Solution

1 back to 1

(The magnitude of the resultant)2
= (1/AB)2+(1/AC)2
= ((AB)2+(AC)2)/((AB)2(AC)2)
=((AB)2+(AC)2)/((AD)2(BC)2)
=(1/AD)2
=> The magnitude of the resultant = 1/AD
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