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1)
B(OH)3 + NaOH → NaBO2 + Na[B(OH)4] + H2O
To keep the above reaction in forward direction, which reagent should be used.
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2)
An aqueous solution of metal salt is given. NH4Cl and NH4OH are
added to it and white precipitate is formed. Some part of precipitate remains in dissolved
state as well. The above solution that dissolves in NH4OH is of
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3)
The gases produced are respectively
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4)
The molar heat capacity of a monoatomic gas for which the ratio of pressure and volume is one
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5)
Arrange the following compounds according to decreasing boiling points.
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a
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(IV) > (III) > (II) > (I)
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b
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(III) > (IV) > (II) > (I)
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c
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(I) > (II) > (III) > (IV)
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d
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(II) > (III) > (I) > (IV)
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6)
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a
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b
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c
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d
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7)
The IUPAC name of C6H5COCl is
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b
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Benzene chloro ketone
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c
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Benzene carbonyl chloride
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8)
Ag+ + NH3
[Ag(NH3)]+ ; kf = 6.8 x 103
[Ag(NH3)]+ + NH3
[Ag(NH3)2]+ ; kf = 1.6 x 103
Overall formation constant of the complex [Ag(NH3)2]+
would be
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9)
CH3NH2 + CHCl3 + KOH →
Nitrogen containing compound + KCl + H2O.
Nitrogen containing compound is
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c
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d
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10)
In blue solution of copper sulpahte excess of KCN is
added then solution becomes colourless due to the
formation of
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b
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Cu2+ get reduced to form [Cu(CN)4]3-
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11)
The direct conversion of A to B is difficult, hence it is carried out by the following shown path:
ΔSA→C = 50 e.u
ΔSC→D = 30 e.u
ΔSB→D = 20 e.u
where e.u. is entropy unit then ΔSA→B is
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12)
In the Haber Basch process, for the preparation of ammonia,
in presence of activated ferrous and
molybdenum, which of the following is correct
N2 + 3H2
2NH3 ; ΔH < 0
Pick the correct answer :
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a
)
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The condition for equilibrium is
2ΔGNH3 =
3ΔGH2 +
ΔGN2
where G is Gibbs free energy per
mole of the gaseous species measured at that partial pressure. The condition of equilibrium is
unaffected by the use of catalyst, which increases the rate of both the forward and backward
reactions to the same extent.
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b
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The equilibrium will shift to forward direction because according
to 2nd law of thermodynamics
the entropy must increases in the direction of spontaneous reaction.
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c
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Catalyst will not alter the rate of either of the reaction.
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d
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Catalyst at 298 K doesn't affect reaction rate as it increase, the forward and backward reaction
by 2 and catalyst at 443 K increase reaction rate in the forward direction by 2 and backward
direction by 1.7
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13)
Section-B (May have more than one option correct)
If the bond length of CO bond in carbon monoxide is 1.128 Å ,
then what is the value of CO bond length in Fe(CO)5 ?
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14)
Section-B (May have more than one option correct)
The species present in solution when CO2 is dissolved in water are
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a
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CO2 , H2CO3 ,
HCO-3 , CO2-3
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15)
Section-B (May have more than one option correct)
is produced on heating a compound with conc. alkali. Which of the compound will
only give this lactone ?
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a
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b
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c
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d
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16)
Section-B (May have more than one option correct)
Identify the major products [P] and [Q] in th efollowing reaction
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a
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b
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c
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d
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17)
Section-B (May have more than one option correct)
The given graph represents the variation of
Z(compressibility factor = (PV)/(nRT) versus P,
at a particular temperature for three real gases A, B and C.
Which of the following statement is incorrect.
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a
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For the gas A, a = 0 and its dependence on P is linear at all pressure
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b
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For the gas B, b = 0 and its dependence on P is linear at all pressure.
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c
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For the gas C, which is typical real gas for which neither a nor b = 0.
By knowing the minima and the point of intersection, with Z = 1, a and b can be calculated.
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d
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At high pressure, the slope is positive for all real gases.
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18)
Section-B (May have more than one option correct)
There is a mixture of lowest molecular weight ketone and its next homologue.
It is treated with hydroxyl amine when a mixture of oximes is obtained.
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a
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Two different oximes are formed
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b
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Three different oximes are formed
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c
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Two oximes are optically active
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d
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All oximes are optically active
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19)
Section-B (May have more than one option correct)
What are M and N ?
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20)
Section-B (May have more than one option correct)
Ammonical solution of MgSO4 in presence of NH4Cl is
heated with Na2HPO4. The white precipitate formed is of
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21)
Section-C (Comprehension-1)
The coordination number of Ni2+ is 4.
NiCl2 + KCN (excess) → A (cyano complex)
The IUPAC name of A and B are
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a
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Potassium tetracyanonickelate (II), potassium tetrachloronickelate (II)
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b
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Tetracyanopotassiumnickelate (II), teterachlorpotassiumnickelate (II)
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c
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Tetracyanornickel (II), tetrachloronickel (II)
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d
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Potassium tetracyanonickel (II), potassium tetrachloronickel (II)
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22)
Section-C (Comprehension-1)
The coordination number of Ni2+ is 4.
NiCl2 + KCN (excess) → A (cyano complex)
Which of the following is correct ?
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a
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Complex (A) is paramagnetic and complex (B) is diamagnetic
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b
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Complex (A) is diamagnetic and complex (B) is paramagnetic
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c
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Complex (A) with cyano is paramagnetic with two unpaired electrons and
complex (B) is diamagnetic
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d
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Complex (A) with cyano is diamagnetic and complex (B) with chloro is
paramagnetic with two unpaired electrons.
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23)
Section-C (Comprehension-1)
The coordination number of Ni2+ is 4.
NiCl2 + KCN (excess) → A (cyano complex)
Hybridisation of the central atom iof complex(A) and complex(B) are
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c
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complex(A):dsp2 and complex(B): sp3
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d
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complex(A): sp3 and complex(B): dsp2
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24)
Section-C (Comprehension-2)
RCONH2 is converted into RNH2 by means of
Hofmann bromamide degradation.
In this reaction, RCONHBr is formed from which this reaction
has derived its name. Electron donating group at phenyl activates
the reaction. Hofmann degradation reaction is an intramolecular reaction.
Which reagent (X) is used to convert I to II
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25)
Section-C (Comprehension-2)
RCONH2 is converted into RNH2 by means of
Hofmann bromamide degradation.
In this reaction, RCONHBr is formed from which this reaction
has derived its name. Electron donating group at phenyl activates
the reaction. Hofmann degradation reaction is an intramolecular reaction.
Which is the rate determining step in Hofmann bromamide degradation?
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26)
Section-C (Comprehension-2)
RCONH2 is converted into RNH2 by means of
Hofmann bromamide degradation.
In this reaction, RCONHBr is formed from which this reaction
has derived its name. Electron donating group at phenyl activates
the reaction. Hofmann degradation reaction is an intramolecular reaction.
What are the constituent amines formed when the mixture of
(i) and (ii) undergoes Hofmann bromamide degradation?
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a
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b
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c
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d
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27)
Section-C (Comprehension-3)
Due to the neutron prsent in cosmic rays, the following reaction takes place by the
bombardment of nitrogen with neutrons
7N14 + 0n1 →
6H14 + 1H1 ;
6C14 → β-
Cosmic rays from 6C14 which get circulated in the atmosphere
as well as in living species. Whenever there is a nuclear explosion , the concentration
of 6C14 increases. both in the atmosphere
as well as in living species. When a species dies the C-14 concentration decreases and
hence the decrease can be measured and the time estimated as to when the organism died.
For this we require
(1) half life of 6C14 (i.e. 5760 years).
(2) Activity of 6C14 in living species.
(3) Activity of 6C14 in fossil.
Beyond 30000 years the age of fossil cannot be determined as the activity then would
be too low.
In radio carbon dating for finding the age of fossils , the most appropriate statement is
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a
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In living organisms, circulation of C-14 from atmosphere is high so the carbon content is constant in
organism
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b
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Carbon dating can be used to find out the age of earth crust and rocks
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c
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Radioactive absorption due to cosmic radiation is equal to the rate of radioactive decay, hence the
carbon content remains constant in living organism
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d
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Carbon dating can not be used to determine concentration of C-14 in dead beings.
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28)
Section-C (Comprehension-3)
Due to the neutron prsent in cosmic rays, the following reaction takes place by the
bombardment of nitrogen with neutrons
7N14 + 0n1 →
6H14 + 1H1 ;
6C14 → β-
Cosmic rays from 6C14 which get circulated in the atmosphere
as well as in living species. Whenever there is a nuclear explosion , the concentration
of 6C14 increases. both in the atmosphere
as well as in living species. When a species dies the C-14 concentration decreases and
hence the decrease can be measured and the time estimated as to when the organism died.
For this we require
(1) half life of 6C14 (i.e. 5760 years).
(2) Activity of 6C14 in living species.
(3) Activity of 6C14 in fossil.
Beyond 30000 years the age of fossil cannot be determined as the activity then would
be too low.
What should be the age of fossil for meaningful determination of its age?
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d
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It can be used to calculate any age
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29)
Section-C (Comprehension-3)
Due to the neutron prsent in cosmic rays, the following reaction takes place by the
bombardment of nitrogen with neutrons
7N14 + 0n1 →
6H14 + 1H1 ;
6C14 → β-
Cosmic rays from 6C14 which get circulated in the atmosphere
as well as in living species. Whenever there is a nuclear explosion , the concentration
of 6C14 increases. both in the atmosphere
as well as in living species. When a species dies the C-14 concentration decreases and
hence the decrease can be measured and the time estimated as to when the organism died.
For this we require
(1) half life of 6C14 (i.e. 5760 years).
(2) Activity of 6C14 in living species.
(3) Activity of 6C14 in fossil.
Beyond 30000 years the age of fossil cannot be determined as the activity then would
be too low.
A nuclear explosion has taken place leading to increase in concentration of C14 in nearby areas. C14
concentration is C1 in nearby areas and C2 in areas far away. If the age of the fossil is determined to be
T1 and T2 at the places respectively then
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a
)
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The age of the fossil will increase at the place where explosion has taken place and
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b
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The age of the fossil will decrease at the place where explosion has taken place and
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c
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The age of fossil will be determined to be same
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30)
(Comprehension-4)
Tollen's reagent is used for the detection of aldehyde when a solution
of AgNO3 is added to glucose with NH4OH then gluconic
acid is formed
Ag+ + e- →
Ag; E°red = 0.8 V
C6H12O6 + H2O →
Gluconic acid ( C6H12O7 ) + 2H+ +
2e- ; E°oxd = -0.05 V
Ag(NH3)2+ + e-
→
Ag(s) + 2NH3 ; E°red = 0.337 V
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[ Use 2.303 x
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R T
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= 0.0592 and
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F
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= 38.92 at 298 K ]
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F
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R T
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2Ag+ + C6H12O6 + H2O →
2Ag(s) + C6H12O7
Calculate lnK for of this reaction.
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31)
(Comprehension-4)
Tollen's reagent is used for the detection of aldehyde when a solution
of AgNO3 is added to glucose with NH4OH then gluconic
acid is formed
Ag+ + e- →
Ag; E°red = 0.8 V
C6H12O6 + H2O →
Gluconic acid ( C6H12O7 ) + 2H+ +
2e- ; E°oxd = -0.05 V
Ag(NH3)2+ + e-
→
Ag(s) + 2NH3 ; E°red = 0.337 V
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[ Use 2.303 x
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R T
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= 0.0592 and
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F
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= 38.92 at 298 K ]
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F
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R T
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When ammonia is added to the solution, pH is raised to 11.
Which half-cell reaction is affected by pH and by how
much?
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a
)
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Eoxd
will increase by a factor of 0.65 from
E°oxd
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b
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Eoxd
will decrease by a factor of 0.65 from
E°oxd
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c
)
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Ered
will increase by a factor of 0.65 from
E°red
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d
)
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Ered
will decrease by a factor of 0.65 from
E°red
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32)
(Comprehension-4)
Tollen's reagent is used for the detection of aldehyde when a solution
of AgNO3 is added to glucose with NH4OH then gluconic
acid is formed
Ag+ + e- →
Ag; E°red = 0.8 V
C6H12O6 + H2O →
Gluconic acid ( C6H12O7 ) + 2H+ +
2e- ; E°oxd = -0.05 V
Ag(NH3)2+ + e-
→
Ag(s) + 2NH3 ; E°red = 0.337 V
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[ Use 2.303 x
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R T
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= 0.0592 and
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F
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= 38.92 at 298 K ]
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F
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R T
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Ammonia is always is added in this reaction. Which of the following must be incorrect?
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a
)
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NH3 combines with Ag+ to form a complex.
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b
)
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Ag(NH3)2+
is a stronger oxidising reagent than Ag+ .
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c
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In absence of NH3 silver salt of gluconic acid is formed.
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d
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NH3 has affected the standard reduction potential of glucose/gluconic acid electrode.
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33)
75.2 g of C6H5OH(phenol) is dissolved in a
solvent of Kf = 14. If the depression in freezing point is 7 K then find the %
of phenol that dimerises.
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34)
For the reaction, 2CO + O2 → 2CO2 ;
ΔH = -560kJ .
Two moles of CO and one mole of O2 are taken in a container
of volume 1 L. They completely form two moles of CO2,
the gases deviate appreciably from ideal behaviour. If the
pressure in the vessel changes from 70 to 40 atm,
find the magnitude (absolute value) of ΔU at 500 K.
(1 L atm = 0.1 kJ)
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35)
We have taken a saturated solution of AgBr.
Ksp of AgBr is 12 x 10-14 . If 10-7
mole of AgNO3 are added to 1 litre of
this solution find conductivity (specific conductance) of this solution in terms of
10-7 S m-1 units.
Given λ°(Ag+) = 6 x 10-3 Sm2mol-1
λ°(Br-) = 8 x 10-3 Sm2mol-1
λ°(NO-3) = 7 x 10-3 Sm2mol-1
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36)
The edge length of unit cell of a metal having molecular weight 75 g/mol is
5 Å
which crystallizes in cubic lattice. If
the density is 2 g/cc then find the radius of metal atom.
(NA = 6 x 1023). Give the answer in pm.
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37)
Match the extraction processes listed in Column I with metals listed in Column II:
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Column I |
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Column II |
| (A) |
Self reduction |
(P) |
Lead |
| (B) |
Carbon reduction |
(Q) |
Silver |
| (C) |
Complex formation and displacement by metal |
(R) |
Copper |
| (D) |
Decomposition of iodide |
(S) |
Boron |
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38)
Match the following:
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Column I |
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Column II |
| (A) |
Bi3+ → (BiO)+ |
(P) |
Heat |
| (B) |
[AlO2]- → Al(OH)3 |
(Q) |
Hydrolysis |
| (C) |
SiO44- → Si2O76- |
(R) |
Acidification |
| (D) |
(B4O72-) → [B(OH)3] |
(S) |
Dilution by water |
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39)
According to Bohr's theory,
En = Total energy
Kn = Kinetic energy
Vn = Potential energy
rn = Radius of nth orbit
Match the following:
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Column I |
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Column II |
| (A) |
Vn/Kn = ? |
(P) |
0 |
| (B) |
If radius of nth orbit
∝ Enx , x = ?
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(Q) |
-1 |
| (C) |
Angular momentum in lowest orbital |
(R) |
-2 |
| (D) |
1/rn ∝ Zy , y=? |
(S) |
1 |
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40)
Match the following:
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Column I |
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Column II |
| (A) |
CH3-CHBr-CD3 on treatment with alc. KOH gives
CH2=CH-CD3 as a major product.
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(P) |
E1 reaction |
| (B) |
Ph-CHBr=CH3 reacts faster than Ph-CHBr-CD3.
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(Q) |
E2 reaction |
| (C) |
Ph-CH2-CH2Br on treatment with
C2H5OD/C2H5O-
gives Ph-CD=CH2 as the major product.
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(R) |
E1cb reaction |
| (D) |
PhCH2CH2Br and PhCD2CH2Br react with same rate.
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(S) |
First order reaction |
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1 back to 1
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2 back to 2
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3 back to 3
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4 back to 4
As per first law of thermodynamics:
dQ = dU + dW
U = (3/2)nRT
In our case n = 1 , because,
molar heat capacity of substance is amount of Heat Energy
required to raise the temperature of 1 mole of the substance by one degree.
U = (3/2)RT
dU = (3/2)R dT ................... (i)
As per gas law,
PV = nRT (in our case n = 1 and P=V) , so
V2 = RT
2V dV = R dT ........................(ii)
Once again, molar heat capacity of substance is amount of Heat Energy
required to raise the temperature of 1 mole of the substance by one degree.
So molar heat capacity = (1/n).(dQ/dt) = dQ/dt (because we are using n=1)
As per first law of thermodynamics:
dQ = dU + dW ........................(iii)
dW = work done by gas = P dV = V dV (because in our case P = V)
dQ = dU + VdV
replave the value of dU and dV from (i) and (ii)
dQ = (3/2)R dT + (R/2) dT
dQ/dT = (3/2)R + (1/2) R = (4/2) R
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5 back to 5
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6 back to 6
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7 back to 7
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8 back to 8
Overall formation constant = Kf(first) x Kf(second)
Overall formation constant = 6.8 x 103 x 1.6 x 103
Overall formation constant = 1.08 x 107
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9 back to 9
This is isocynaide test
This reaction is known as Carbylamine reaction
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10 back to 10
Cu2+ + 2CN- → Cu(CN)2
2Cu(CN)2 → 2CuCN + (CN)2
CuCN + 3 KCN → [Cu(CN)4]3- + 3K+
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11 back to 11
ΔSA→B =
ΔSA→C +
ΔSC→D -
ΔSB→D
ΔSA→B = = 50 + 30 - 20 = 60
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12 back to 12
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13 back to 13
The bonding between CO and metal (Fe), strengthens the bond between CO.
Due to this CO bond length contracts.
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14 back to 14
CO2 + H2O
H2CO3
H+ + HCO-3
H+ + CO2-3
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15 back to 15
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16 back to 16
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17 back to 17
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18 back to 18
Me - Co - Me is the lowest weight of ketone.
Its next higher homolouge is MeCH2-CO-Me
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Mg2+ + NH3 + HPO2-4 →
MgNH4PO4 ↓
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The migration of p-chlorophenyl group of N-atom is the slowest step. So the
formation of isocynate is rate determining step.
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If concentration of NH3 increases then, the concentration of H+
ion decreases. Therefore, Ered increases.
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75%
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557 kJ
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55 Sm-1
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55 Sm-1
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A → P,R ; B → P,R ; C → Q ; D → S
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A → Q; B → R; C → P; D → Q,R
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A → R ; B → Q ; C → P ; D → S
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A → Q ; B → Q ; C → R,S ; D → P,S
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